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[Mark]

hello

im using this to display my records in a table with pagination but it will show all the records but i want it do it only shows the records that the username put in to the database i tried this.

below shows all the records

Code: Select all

$sql = 'SELECT * FROM orders LIMIT '.$page1.', 4';

this is ment to just show the records off the person logged in but seems to get an error.

Code: Select all

$sql = 'SELECT * FROM orders  WHERE OrderBy = '$username'LIMIT '.$page1.', 4';

[CodenStuff]

hello

im using this to display my records in a table with pagination but it will show all the records but i want it do it only shows the records that the username put in to the database i tried this.

below shows all the records

Code: Select all

$sql = 'SELECT * FROM orders LIMIT '.$page1.', 4';

this is ment to just show the records off the person logged in but seems to get an error.

Code: Select all

$sql = 'SELECT * FROM orders  WHERE OrderBy = '$username'LIMIT '.$page1.', 4';

Maybe try:

Code: Select all

$sql = "SELECT * FROM orders WHERE OrderBy = '$username' LIMIT '.$page1.', 4";

Unsure if that will work but let me know either way.

[CodenStuff]

Also what is the error?

[Livengood]

Might have been a small error in your code that was provided. Sometimes its a bit buggy when you try and place variables into a string. Can you try the following?

When you are using LIMIT, you are passing a number, make sure to also leave out the '.

Code: Select all

$sql = "SELECT * FROM orders WHERE OrderBy = '{$username}' LIMIT {$page1}, 4";

Code: Select all

$sql = 'SELECT * FROM orders WHERE OrderBy = '" . $username . "' LIMIT '" . $page1 . "', 4';